A 5.8 kg box is on a frictionless 37 ∘ slope and is connected via a massless string over a massless, frictionless pulley to a hanging 1.7 kg weight.What is the tension in the string once the box begins to move?
Accepted Solution
A:
Answer:T=20.62 NStep-by-step explanation: Given[tex]m_1=5.8 kg[/tex][tex]m_2=1.7 kg[/tex]inclination [tex]\theta =37^{\circ}[/tex]Let T be the tensionFrom diagram [tex]5.8 g\sin\theta -T=5.8 a[/tex][tex]5.8 g\sin\theta -5.8 a=T[/tex]---1 For [tex]m_2[/tex] block[tex]T-1.7 g=1.7 a[/tex][tex]T=1.7(g+a)[/tex]--2from 1 & 2 we get[tex]1.7(g+a)=5.8 g\sin\theta -5.8 a[/tex][tex]7.5 a=5.8g\sin \theta -1.7g[/tex][tex]7.5 a=1.79 g[/tex][tex]a=\frac{1.79 g}{7.5}=0.238 g=2.33 m/s^2[/tex][tex]T=1.7(9.8+2.33)=1.7\times 12.132[/tex][tex]T=20.62 N[/tex]